And as there is the formation of five hybridized orbitals for this molecule, Phosphorus has sp3d hybridization in PF5. All these five orbitals accommodate one valence electron of the Fluorine atoms. There are five half-filled orbitals: one s orbital, three p orbitals, and one d orbital. The electron configuration of a Phosphorus atom in its ground state is 1s2 2s2 2p6 3s2 3p3, but when it is in an excited state, the electrons from 3s orbital get unpaired. There are no lone pairs in the Lewis Structure of PF 5, and there are five single bonds between Phosphorus and Fluorine atoms. Phosphorus here now has more than eight valence electrons in its outer shell because it has extra hybridized orbitals to accommodate more electrons. Doing so, the octets of all Fluorine atoms will be completed. Each Fluorine atom will share one valence electron of the Phosphorus atom. So Phosphorus atoms will be in the center, and all the Fluorine atoms will be arranged around it.Р”Р„ll Fluorine atoms here need one valence electron to complete their octet. Here Phosphorus atom will take the central position as it is less electronegative than the Fluorine atoms. This structure helps us understand the electrons that take part in forming bonds and the arrangement of electrons in the molecule. Lewis Structure of a molecule is a pictorial representation of the arrangement of atoms in the molecule.

Thus, there are a total of 40 valence electrons for PF 5.

Total number of valence electrons РІР‚вЂњ 5 + 35 So we have 35 valence electrons for all Fluorine atoms. Phosphorus has 5 valence electrons in its outer shell.Р”Р‡luorine has 7 valence electrons in its outer shell, but as there are 5 fluorine atoms, we will multiply the number by 5. The total number of valence electrons in PF 5 : Valence electrons of Phosphorus + Valence electrons of Fluorine.

Sp3d orbital